Three boys and two girls stand in a queue. The probability that the number of boys ahead of every girl is atleast one more than the number of girls ahead of her is

Step-by-step solution

Either a girl start the sequence or will be at second position and will not acquire the last position as well. Required probability =   3 C 2 × 2 ! × 3 ! +   2   C 1 × 2 ! × 3 !   5 ! = 1 2