JEE Advanced 2025Paper 1
- Exam
- JEE Advanced
- Year
- 2025
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Vector Algebra
JEE Advanced 2025 · Paper 1 · Mathematics · Vector Algebra
For any two points M and N in the X Y -plane, let M N denote the...
For any two points and in the -plane, let denote the vector from to , and denote the zero vector. Let and be three distinct points in the -plane. Let be a point inside the triangle such that . Let and be the mid-points of the sides and , respectively. Then the value of is ________
Correct answer
0
Step-by-step solution
\begin{aligned}
&\because \overrightarrow{\mathrm{SP}}+5 \overrightarrow{\mathrm{SQ}}+6 \overrightarrow{\mathrm{SP}}=\overrightarrow{0}\\
&\text{ (Let P.V.\text{ of } } P \text{ be } \vec{p}, Q \text{ be } \vec{q} \text{ and } R \text{ be } \vec{r} \text{ ) }\\
&\begin{aligned}
& \Rightarrow(\vec{p}-\vec{s})+5(\vec{q}-\vec{s})+6(\vec{r}-\vec{s})=\overrightarrow{0} \\
& \Rightarrow \vec{S}=\frac{\vec{p}+5 \vec{q}+6 \vec{r}}{12} \\
& \Rightarrow \overrightarrow{E F}=\left(\frac{\vec{q}-\vec{p}}{2}\right) \\
& \Rightarrow \overrightarrow{E S}=\left(\frac{5 \vec{q}-5 \vec{p}}{12}\right)=\frac{5}{12}(\vec{q}-\vec{p}) \\
& \therefore \frac{|\overrightarrow{E F}|}{|\overrightarrow{E S}|}=\frac{6}{5}=1.2
\end{aligned}
\end{aligned}$