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JEE Advanced 2017Paper 2
Exam
JEE Advanced
Year
2017
Paper
Paper 2
Subject
Mathematics
Chapter
Vector Algebra

JEE Advanced 2017 · Paper 2 · Mathematics · Vector Algebra

Paragraph: Let O be the origin, and O X , O Y , O Z be three unit...

Paragraph: Let OO be the origin, and OX→,OY→,OZ→\overrightarrow{O X}, \overrightarrow{O Y}, \overrightarrow{O Z} be three unit vectors in the directions of the sides QR→,RP→\overrightarrow{Q R}, \overrightarrow{R P}, PQ→\overrightarrow{P Q}, respectively, of a triangle PQRP Q R.
Question: ∣OX→×OY→∣=|\overrightarrow{O X} \times \overrightarrow{O Y}|=Paragraph: Let O be the origin, and O X , O Y , O Z be three unit vectors in the directions of the sides Q R , R P , P

Options

  1. Asin⁡(P+Q)\sin \left(P + Q\right)
  2. Bsin⁡2R\sin 2R
  3. Csin⁡(P+R)\sin \left(P + R\right)
  4. Dsin⁡(Q+R)\sin \left(Q + R\right)

Correct answer

A. sin⁡(P+Q)\sin \left(P + Q\right)

Step-by-step solution

OX→,OY→,OZ→\overset{\to}{OX}, \overset{\to}{OY}, \overset{\to}{OZ} are unit vectors in the directions of sides OR→,RP→\overset{\to}{OR}, \overset{\to}{RP} and PQ→\overset{\to}{PQ} respectively,

Paragraph: Let O be the origin, and O X , O Y , O Z be three unit vectors in the directions of the sides Q R , R P , P

∴OX→=QR→∣QR→∣,OY→=RP→∣RP→∣,OZ→=PQ→∣PQ→∣∴ \overset{\to}{OX} = \overset{\to}{QR}\left|\overset{\to}{QR}\right|, \overset{\to}{OY} = \overset{\to}{RP}\left|\overset{\to}{RP}\right|, \overset{\to}{OZ} = \overset{\to}{PQ}\left|\overset{\to}{PQ}\right|

∴∣OX→×OY→∣=∣OR→×RP→∣∣QR→∣∣RP→∣∴ \left|\overset{\to}{OX} \times \overset{\to}{OY}\right| = \dfrac{\left|\overset{\to}{OR} \times \overset{\to}{RP}\right|}{\left|\overset{\to}{QR}\right|\left|\overset{\to}{RP}\right|}

=∣QR→∣∣RP→∣sin⁡(P+Q)∣QR→∣∣RP→∣= \dfrac{\left|\overset{\to}{QR}\right|\left|\overset{\to}{RP}\right|\sin \left(P + Q\right)}{\left|\overset{\to}{QR}\right|\left|\overset{\to}{RP}\right|}

=sin⁡(P+Q)= \sin \left(P + Q\right)

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