JEE Advanced 2015Paper 1
- Exam
- JEE Advanced
- Year
- 2015
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Vector Algebra
JEE Advanced 2015 · Paper 1 · Mathematics · Vector Algebra
Let PQR be a triangle. Let → a = → QR , → b = → RP and → c = → PQ ....
Let \overset{\to}{a} = \overset{\to}{QR}, \overset{\to}{b} = \overset{\to}{RP}and\overset{\to}{c} = \overset{\to}{PQ} . and then which of the following is (are) true ?
Options
- A
- B
- C
- D\overset{\to}{a} ⋅ \overset{\to}{b} = - 72
Correct answer
A.
Step-by-step solution
\left|\overset{\to}{a}\right| = 12, \left|\overset{\to}{b}\right| = 4\sqrt{3}, \overset{\to}{b .}\overset{\to}{c} = 24\overset{\to}{a} + \overset{\to}{b} + \overset{\to}{c} = 0\overset{\to}{b} + \overset{\to}{c} = - \overset{\to}{a}
\left|\overset{\to}{a} \times \overset{\to}{b} + \overset{\to}{c} \times \overset{\to}{a}\right| = \left|\overset{\to}{a} \times \overset{\to}{b} - \overset{\to}{a} \times \overset{\to}{c}\right|= \left|\overset{\to}{a} \times \left(\overset{\to}{b} - \overset{\to}{c}\right)\right|\overset{\to}{a} = - \overset{\to}{b} - \overset{\to}{c}= \left|\left(- \overset{\to}{b} - \overset{\to}{c}\right) \times \left(\overset{\to}{b} - \overset{\to}{c}\right)\right| = \left|\left(\overset{\to}{b} - \overset{\to}{c}\right) \times \left(\overset{\to}{b} + \overset{\to}{c}\right)\right|= 2\left|\overset{\to}{b} \times \overset{\to}{c}\right|= 2\sqrt{{\left|\overset{\to}{b}\right|}^{2}{\left|\overset{\to}{c}\right|}^{2} - {\left(\overset{\to}{b} . \overset{\to}{c}\right)}^{2}} = 2\sqrt{48 \times 48 - {\left(24\right)}^{2}}= 2 \times 24\sqrt{4 - 1} = 48\sqrt{3}\overset{\to}{a} + \overset{\to}{b} = - \overset{\to}{c}
\left|\overset{\to}{a} \times \overset{\to}{b} + \overset{\to}{c} \times \overset{\to}{a}\right| = \left|\overset{\to}{a} \times \overset{\to}{b} - \overset{\to}{a} \times \overset{\to}{c}\right|= \left|\overset{\to}{a} \times \left(\overset{\to}{b} - \overset{\to}{c}\right)\right|\overset{\to}{a} = - \overset{\to}{b} - \overset{\to}{c}= \left|\left(- \overset{\to}{b} - \overset{\to}{c}\right) \times \left(\overset{\to}{b} - \overset{\to}{c}\right)\right| = \left|\left(\overset{\to}{b} - \overset{\to}{c}\right) \times \left(\overset{\to}{b} + \overset{\to}{c}\right)\right|= 2\left|\overset{\to}{b} \times \overset{\to}{c}\right|= 2\sqrt{{\left|\overset{\to}{b}\right|}^{2}{\left|\overset{\to}{c}\right|}^{2} - {\left(\overset{\to}{b} . \overset{\to}{c}\right)}^{2}} = 2\sqrt{48 \times 48 - {\left(24\right)}^{2}}= 2 \times 24\sqrt{4 - 1} = 48\sqrt{3}\overset{\to}{a} + \overset{\to}{b} = - \overset{\to}{c}