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JEE Advanced 2011Paper 2
Exam
JEE Advanced
Year
2011
Paper
Paper 2
Subject
Physics
Chapter
Alternating Current

JEE Advanced 2011 · Paper 2 · Physics · Alternating Current

A series R - C circuit is connected to A C voltage source. Consider...

A series RR - CC circuit is connected to ACA C voltage source. Consider two cases; (A)(A) when CC is without a dielectric medium and (B)(B) when CC is filled with dielectric of constant 4. The current IRI_R through the resistor and voltage VCV_C across the capacitor are compared in the two cases. Which of the following is/are true?

Options

  1. AIRA>IRBI_R^A>I_R^B
  2. BIRA<IRBI_R^A < I_R^B
  3. CVCA>VCBV_C^A>V_C^B
  4. DVCA<VCBV_C^A < V_C^B

Correct answer

B. IRA<IRBI_R^A < I_R^B

Step-by-step solution

Z=\sqrt{R^2+X_C^2}=\sqrt{R^2+\left(\frac{1}{\omega C}\right)^2} In case (b) capacitance CC will be more. Therefore, impedance ZZ will be less. Hence, current will be more. ∴\therefore Option (b) is correct. Further, \quadVC=V2−VR2=V2−(IR)2\begin{aligned} V_C & =\sqrt{V^2-V_R^2} \\ & =\sqrt{V^2-(I R)^2}\end{aligned}$Incase(b),sincecurrentIn case (b), since currentIismore.Therefore,is more. Therefore,V_Cwillbeless.will be less.\thereforeOption(c)iscorrect.Option (c) is correct.\thereforeCorrectoptionsare(b)and(c).AnalysisofQuestion(i)Questionismoderatelydifficult.(ii)Inmyopinionproblemsofalternatingcurrentsarenotverydifficult.(iii)TopicofCorrect options are (b) and (c). Analysis of Question (i) Question is moderately difficult. (ii) In my opinion problems of alternating currents are not very difficult. (iii) Topic ofA C$ is small. One can feel comfortable in this topic by putting less efforts.
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