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JEE Advanced 2017Paper 1
Exam
JEE Advanced
Year
2017
Paper
Paper 1
Subject
Physics
Chapter
Atomic Physics

JEE Advanced 2017 · Paper 1 · Physics · Atomic Physics

An electron in a hydrogen atom undergoes a transition from an orbit...

An electron in a hydrogen atom undergoes a transition from an orbit with a quantum number ni{n}_{i} to another quantum number nf{n}_{f} . ViandVf{V}_{i}\text{and}{V}_{f} are the initial and final potential energies of the electron. If ViVf=6.25\dfrac{{V}_{i}}{{V}_{f}} = 6.25 then the smallest nf{n}_{f} is

Correct answer

5

Step-by-step solution

U=−Z2n2E0U = - \dfrac{{Z}^{2}}{{n}^{2}}{E}_{0}

Z=1Z = 1

U=−E0n2U = - \dfrac{{E}_{0}}{{n}^{2}}

UiUf=nf2ni2=6.25\dfrac{{U}_{i}}{{U}_{f}} = \dfrac{{n}_{f}^{2}}{{n}_{i}^{2}} = 6.25

Taking ni=2{n}_{i} = 2

nf=5{n}_{f} = 5

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