A hydrogen atom in its ground state is irradiated by light of wavelength 970Å . Taking hc/e = 1.237 × 10 ^ - 6 eV m and the ground state energy of hydrogen atom as - 13.6eV , the number of lines present in the emission

Correct answer: 6 (hc)/(λ) = (12370)/(970) - 13.6 + 12.7 = - 13.6 n ^ 2 n ^ 2 = 16 n = 4 Number of lines = n C _ 2 = 6

JEE Advanced 2016Paper 1

JEE Advanced 2016 · Paper 1 · Physics · Atomic Physics

A hydrogen atom in its ground state is irradiated by light of...

A hydrogen atom in its ground state is irradiated by light of wavelength

970Å .

Taking hc/e =

1.237 \times {10}^{- 6}eV

m and the ground state energy of hydrogen atom as

- 13.6eV

, the number of lines present in the emission spectrum is

\dfrac{hc}{\lambda} = \dfrac{12370}{970}

- 13.6 + 12.7 = - \dfrac{13.6}{{n}^{2}}

{n}^{2} = 16

n = 4

Number of lines

= n{C}_{2} = 6