JEE Advanced2009PhysicsAtomic PhysicsActual
Paragraph: When a particle is restricted to move along x -axis between x=0 and x=a , where a is of nanometer dimension, its energy can take only certain specific values. The allowed energies of the particle moving in such a restricted region, correspond to the formation of standing waves with nodes at its ends x=0 and x=a . The wavelength of this standing wave is related to the liner momentum p of the particle accord
Options
- A0.8 meV
- B8 meV
- C80 meV
- D800 meV
Correct answer
B. 8 meV
Step-by-step solution
From Eq. (i) E= n^2 h^2 8 a^2 m In ground state n=1 E₁= h^2 8 m a^2 Substituting the values, we get E₁=8 meV