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JEE Advanced 2013Paper 1
Exam
JEE Advanced
Year
2013
Paper
Paper 1
Subject
Physics
Chapter
Kinetic Theory of Gases

JEE Advanced 2013 · Paper 1 · Physics · Kinetic Theory of Gases

Two non-reactive monoatomic ideal gases have their atomic masses in...

Two non-reactive monoatomic ideal gases have their atomic masses in the ratio 2 : 3. The ratio of their partial pressures, when enclosed in a vessel kept at a constant temperature, is 4 : 3. The ratio of their densities is

Options

  1. A1 : 4
  2. B1 : 2
  3. C6 : 9
  4. D8 : 9

Correct answer

D. 8 : 9

Step-by-step solution

Given, mAmB=23\dfrac{{\text{m}}_{\text{A}}}{{\text{m}}_{\text{B}}} = \dfrac{2}{3 }
∵∵ Volume and temperature is same.
From ideal gas equation, PV=nRTPV = nRT
Pn=constant\dfrac{\text{P}}{\text{n}} = constant
PAnA=PBnB⇒nAnB=PAPB=43\dfrac{{\text{P}}_{\text{A}}}{{\text{n}}_{\text{A}}} = \dfrac{{\text{P}}_{\text{B}}}{{\text{n}}_{\text{B}}} ⇒ \dfrac{{\text{n}}_{\text{A}}}{{\text{n}}_{\text{B}}} = \dfrac{{\text{P}}_{\text{A}}}{{\text{P}}_{\text{B}}} = \dfrac{4}{3}

Also, density, ρ=MVρ = \dfrac{M}{V}
ρAρB=MA/vMB/v=nAmAnBmB\dfrac{{\text{ρ}}_{\text{A}}}{{\text{ρ}}_{\text{B}}} = \dfrac{{\text{M}}_{\text{A}} / \text{v}}{{\text{M}}_{\text{B}} / \text{v}} = \dfrac{{\text{n}}_{\text{A}} {m}_{\text{A}}}{{\text{n}}_{\text{B}} {\text{m}}_{\text{B}}}
=43×23=89= \dfrac{4}{3} \times \dfrac{2}{3} = \dfrac{8}{9}.

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