JEE Advanced2025PhysicsLaws of MotionActual
A person sitting inside an elevator performs a weighing experiment with an object of mass 50 kg . Suppose that the variation of the height y (in m ) of the elevator, from the ground, with time t (in s ) is given by y=8 [1+ ( 2 t T ) ] , where T=40 ~s . Taking acceleration due to gravity, g=10 ~m / s ^2 , the maximum variation of the object's weight (in N ) as observed in the experiment is _______ .
Correct answer
0
Step-by-step solution
y=8+8 2 t T With respect to elevator, variation in weight will be aligned & W = m ( a )_ & W = m 2 ^2 ~A aligned Here elevator is performing SHM aligned & W =2 ~m ( 2 ~T )^2 A N & W =2 50 ( 2 40 )^2 8 ~N & ~W =2 50 1 400 8 ~N & ~W = 800 400 ~N =2 ~N aligned