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JEE Advanced 2016Paper 2
Exam
JEE Advanced
Year
2016
Paper
Paper 2
Subject
Physics
Chapter
Laws of Motion

JEE Advanced 2016 · Paper 2 · Physics · Laws of Motion

Paragraph: A frame of reference that is accelerated with respect to...

Paragraph: A frame of reference that is accelerated with respect to an inertial frame of reference is called a non-inertial frame of reference. A coordinate system fixed on a circular disc rotating about a fixed axis with a constant angular velocity ω\omega is an example of a non-inertial frame of reference. The relationship between the force F⃗rot \vec{F}_{\text{rot }} experienced by a particle of mass mm moving on the rotating disc and the force F⃗in \vec{F}_{\text{in }} experienced by the particle in an inertial frame of reference is F⃗rot=F⃗in+2m(v⃗rot×ω⃗)+m(ω⃗×r⃗)×ω⃗\vec{F}_{\mathrm{rot}}=\vec{F}_{\mathrm{in}}+2 m\left(\vec{v}_{\mathrm{rot}} \times \vec{\omega}\right)+m(\vec{\omega} \times \vec{r}) \times \vec{\omega}, where v⃗rot \vec{v}_{\text{rot }} is the velocity of the particle in the rotating frame of reference and r⃗\vec{r} is the position vector of the particle with respect to the centre of the disc. Now consider a smooth slot along a diameter of a disc of radius RR rotating counter-clockwise with a constant angular speed ω\omega about its vertical axis through its center. We assign a coordinate system with the origin at the center of the disc, the xx-axis along the slot, the yy-axis perpendicular to the slot and the zz-axis along the rotation axis (ω⃗=ωk^).(\vec{\omega}=\omega \hat{k}) . A small block of mass mm is gently placed in the slot at r⃗=(R/2)i^\vec{r}=(R / 2) \hat{i} at t=0t=0 and is constrained to move only along the slot. Paragraph: A frame of reference that is accelerated with respect to an inertial frame of reference is called a

Question: The net reaction of the disc on the block is

Options

  1. A- m{\omega}^{2}Rcos \omegat\overset{^}{j} - mg\overset{^}{k}
  2. Bm{\omega}^{2}Rsin \omegat\overset{^}{j} - mg\overset{^}{k}
  3. C\dfrac{1}{2}m{\omega}^{2}R\left({e}^{\omegat} - {e}^{- \omegat}\right)\overset{^}{j} + mg\overset{^}{k}
  4. D\dfrac{1}{2}m{\omega}^{2}R\left({e}^{2\omegat} - {e}^{- 2\omegat}\right)\overset{^}{j} + mg\overset{^}{k}

Correct answer

C. \dfrac{1}{2}m{\omega}^{2}R\left({e}^{\omegat} - {e}^{- \omegat}\right)\overset{^}{j} + mg\overset{^}{k}

Step-by-step solution

Paragraph: A frame of reference that is accelerated with respect to an inertial frame of reference is called a
{\overset{\to}{N}}_{1} = mg\overset{^}{k}
{\overset{^}{N}}_{2} = 2m\left({V}_{rot}^{′} \times \overset{\to}{\omega}\right)\overset{^}{j}
= 2m\left[\dfrac{\omegaR}{4}\left({e}^{\omegat} - {e}^{- \omegat}\right)\right]\omega\overset{^}{j}
= \dfrac{1}{2}m{\omega}^{2}R\left({e}^{\omegat} - {e}^{- \omegat}\right)\overset{^}{j}
Total reaction on block =N→1+N→2= {\overset{\to}{N}}_{1} + {\overset{\to}{N}}_{2}
= \dfrac{1}{2}m{\omega}^{2}R\left({e}^{\omegat} - {e}^{- \omegat}\right)\overset{^}{j} + mg\overset{^}{k}
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