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JEE Advanced 2014Paper 2
Exam
JEE Advanced
Year
2014
Paper
Paper 2
Subject
Physics
Chapter
Laws of Motion

JEE Advanced 2014 · Paper 2 · Physics · Laws of Motion

A block of mass m _ 1 = 1kg another mass m _ 2 = 2kg , are placed...

A block of mass m1=1kg{m}_{1} = 1kg another mass m2=2kg{m}_{2} = 2kg , are placed together (see figure) on an inclined plane with angle of inclination θ\theta . Various values of θ\theta are given in List I. The coefficient of friction between the block m1andtheplaneisalwayszero.Thecoefficientofstaticanddynamicfrictionbetweentheblock{m}_{1} and the plane is always zero. The coefficient of static and dynamic friction between the block{m}_{2}andtheplaneareequaltoand the plane are equal to\mu = 0.3.InListIIexpressionsforthefrictionontheblock. In List II expressions for the friction on the block{m}_{2}aregiven.MatchthecorrectexpressionofthefrictioninListIIwiththeanglesgiveninListI,andchoosethecorrectoption.Theaccelerationduetogravityisdenotedbyg.<br>[Usefulinformation:are given. Match the correct expression of the friction in List II with the angles given in List I, and choose the correct option. The acceleration due to gravity is denoted by g.<br >[Useful information:\tan \left({5.5}^{o}\right) \approx 0.1; \tan \left({11.5}^{o}\right) \approx 0.2; \tan \left({16.5}^{o}\right) \approx 0.3]<br><imgsrc="https://cdn−question−pool.getmarks.app/pyq/jeeadvanced/image19−4c601489−7ed8−4d4e−8d55−e637537cc491.png"/><br/> </p><tableborder="1"><tbody><tr><td> </td><td>ListI</td><td> </td><td>ListII</td></tr><tr><td>A.</td><td>]<br ><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_advanced/image19-4c601489-7ed8-4d4e-8d55-e637537cc491.png"/><br/> </p><table border="1"><tbody><tr><td> </td><td>List I</td><td> </td><td>List II</td></tr><tr><td>A.</td><td>\theta = {5}^{o}</td><td></td><td>P .m2gsinθ{m}_{2}gsin \thetaB.θ=10o\theta = {10}^{o}Q.</td><td>(m1+m2)gsinθQ .</td><td>\left({m}_{1} + {m}_{2}\right)gsin \thetaC.θ=15o\theta = {15}^{o}R.</td><td>R .</td><td>\mu{m}_{2}gcos \theta</td></tr><tr><td>D.</td><td></td></tr><tr><td>D.</td><td>\theta = {20}^{o}</td><td></td><td>S .μ(m1+m2)gcosθ\mu\left({m}_{1} + {m}_{2}\right)gcos \theta

Options

  1. Aa-q;b-q;c-r;d-r;
  2. Ba-q;b-s;c-p;d-r;
  3. Ca-q;b-p;c-s;d-r;
  4. Da-r;b-p;c-s;d-q;

Correct answer

A. a-q;b-q;c-r;d-r;

Step-by-step solution

Condition for not sliding,
{f}_\max > \left({m}_{1} + {m}_{2}\right)gsin \theta
\muN>(m1+m2)gsinθ\muN > \left({m}_{1} + {m}_{2}\right)gsin \theta
0.3m2gcosθ≥30sinθ0.3{m}_{2}gcos \theta \ge 30sin \theta
6≥30tanθ6 \ge 30tan \theta
15≥tanθ\dfrac{1}{5} \ge tan \theta
0.2≥tanθ0.2 \ge tan \theta
∴∴ for P, Q
f=(m1+m2)gsinθf = \left({m}_{1} + {m}_{2}\right)gsin \theta
For R and S
F=fmax=μm2gsinθF = {f}_{max = \mu{m}_{2}gsin \theta}

A block of mass m _ 1 = 1kg another mass m _ 2 = 2kg , are placed together (see figure) on an inclined plane with angle

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