A block is moving on an inclined plane making an angle 45^ with the horizontal and the coefficient of friction is . The force required to just push it up the inclined plane is 3 times the force required to just prevent it from sliding down. If we define N=10 , then N is

Step-by-step solution

aligned & F₁=m g + m g & F₂=m g - m g aligned Given that, F₁=3 F₂ or ( 45^ + 45^ ) =3 ( 45^ - 45^ ) On solving, we get =0.5 N=10 =5 Answer is 5 . Analysis of Question Question is simple. Only one has to take care of direction and magnitude of friction.