System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass $2 m$ and $m$ just after the string is cut will be

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System shown in figure is in equilibrium and at rest. The spring and string are massless, now the string is cut. The acceleration of mass 2 m and m just after the string is cut will be

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Correct answer: A. g / 2 upwards, g downwards

Initially under equilibrium of mass ' m ' T=m g Now, the string is cut. Therefore, T=m g force is decreased on mass m upwards and downwards on mass 2 m . a_m= (m g)/(m)= g (downwards) and a_ 2 m = (m g)/(2 m)=(g)/(2) (upwards)

System shown in figure is in equilibrium and at rest. The spring...

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