List- I shows different radioactive decay processes and List- II provides possible emitted particles. Match each entry in List- I with an appropriate entry from List- II , and choose the correct option. List- I List- II P 238 92 U → 234 91 P a 1 one α particle and one β + particle Q 214 82 P b → 210 82 P b 2 three β - particles and one α particle R 210 81 T l → 206 82 P b 3 two &

Step-by-step solution

In α decay mass number decreases by 4 unit and atomic number decreases by 2 unit. In β - decay mass number does not change but atomic number increases by 1 unit. In β + decay mass number does not change but atomic number decreases by 1 unit. So for P   238 92 U → 234 91 P a . Number of alpha particle = 238 - 234 4 = 1 . Due to alpha particle, atomic number should decrease by 2 but it has decreased by 1 only, therefore an additional β - decay is required, then net change in atomic numb