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JEE Advanced2013PhysicsNuclear PhysicsActual

Paragraph: The mass of a nucleus _ Z ^ A X is less than the sum of the masses of (A-Z) number of neutrons and Z number of protons in the nucleus. The energy equivalent to the corresponding mass difference is known as the binding energy of the nucleus. A heavy nucleus of mass M can break into two light nuclei of masses m₁ and m₂ only if (m₁+m₂ ) M . Also two light nuclei of masses m₃ and m₄ can undergo complete fusion

Options

  1. AThe nucelus 3 6 Li can emit an alpha particle.
  2. BThe nucleus 84 210 Po can emit a proton.
  3. CDeuteron and alpha particle can undergo complete fusion.
  4. DThe nuclei 30 70 Zn and 34 82 Se can undergo complete fusion.

Correct answer

C. Deuteron and alpha particle can undergo complete fusion.

Step-by-step solution

(A)   3 Li 7 → 2 He 4 + 1 H 3 Δ m = M Li - M He - M H 3 = 6.01513 - 4.002603 - 3.016050 = - 1.003523 u Δ m is negative so reaction n is not possible. (B)   84 Po 210 → 83 Bi 209 + 1 P 1 Δ m is negative so reaction is not possible. (C)   1 H 2 → 2 He 4 + 3 Li 6 Δ m is positive so reaction is possible. (D)   30 Zn 70 + 34 Se 82 → 64 Gd 152 Δ m is positive so reaction is not possible.

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