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JEE Advanced2012PhysicsNuclear PhysicsActual

The -decay process, discovered around 1900 , is basically the decay of a neutron (n) . In the laboratory, a proton (p) and an electron (e⁻ ) are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a two-body decay process, it was predicted theoretically that the kinetic energy of the electron should be a constant. But experimentally, it was observed that the electron kineti

Options

  1. AZero
  2. BMuch less than 0.8 10⁶ eV .
  3. CNearly 0.8 10⁶ eV
  4. DMuch larger than 0.8 10⁶ eV

Correct answer

C. Nearly 0.8 10⁶ eV

Step-by-step solution

K_ p ⁻+K_ e ⁻+K_ v ⁻=0.8 10⁶ eV When K_ e ⁻=0 then K_ p ⁻+K_ v ⁻=0.8 10⁶ eV Mass of v < < P maximum energy of anti-neutrino is nearly 0.8 10⁶ eV .

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