JEE Advanced2012PhysicsNuclear PhysicsActual
The -decay process, discovered around 1900 , is basically the decay of a neutron (n) . In the laboratory, a proton (p) and an electron (e⁻ ) are observed as the decay products of the neutron. Therefore, considering the decay of a neutron as a two-body decay process, it was predicted theoretically that the kinetic energy of the electron should be a constant. But experimentally, it was observed that the electron kineti
Options
- AZero
- BMuch less than 0.8 10⁶ eV .
- CNearly 0.8 10⁶ eV
- DMuch larger than 0.8 10⁶ eV
Correct answer
C. Nearly 0.8 10⁶ eV
Step-by-step solution
K_ p ⁻+K_ e ⁻+K_ v ⁻=0.8 10⁶ eV When K_ e ⁻=0 then K_ p ⁻+K_ v ⁻=0.8 10⁶ eV Mass of v < < P maximum energy of anti-neutrino is nearly 0.8 10⁶ eV .