JEE Advanced2013PhysicsUnits and DimensionsActual
Match List I with List II and select the correct answer using the codes given below the lists: List I List II a. Boltzmann constant p. ML 2 T -1 b. Coefficient of viscosity q. ML -1 T -1 c. Planck constant r. MLT - 3 K -1 d. Thermal conductivity s. ML 2 T - 2 K -1
Options
- Aa-s;b-r;c-p;d-q;
- Ba-s;b-r;c-p;d-q;
- Ca-r;b-s;c-q;d-p;
- Da-s;b-q;c-p;d-r;
Correct answer
D. a-s;b-q;c-p;d-r;
Step-by-step solution
(a) U = 1 2 k T ⇒ ML 2 T - 2 = k K ⇒ K = ML 2 T - 2 K -1 (b) F = η A d v d x ⇒ η = MLT - 2 L 2 LT -1 L -1 = ML -1 T -1 (c) E = h ν ⇒ ML 2 T - 2 = h T -1 ⇒ h = ML 2 T -1 (d) d Q d t = k A Δ θ ℓ ⇒ k = ML 2 T - 3 L L 2 K = MLT - 3 K -1