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JEE Advanced 2011Paper 1
Exam
JEE Advanced
Year
2011
Paper
Paper 1
Subject
Physics
Chapter
Units and Dimensions

JEE Advanced 2011 · Paper 1 · Physics · Units and Dimensions

Paragraph: A dense collection of equal number of electrons and...

Paragraph: A dense collection of equal number of electrons and positive ions is called neutral plasma. Certain solids containing fixed positive ions surrounded by free electrons can be treated as neutral plasma. Let NN be the number density of free electrons, each of mass mm. When the electrons are subjected to an electric field, they are displaced relatively away from the heavy positive ions.If the electric field becomes zero, the electrons being to oscillate about the positive ions with a natural angular frequency ωp\omega_p, which is called the plasma frequency. To sustain the oscillations, a time varying electric field needs to be applied that has an angular frequency ω\omega, where a part of the energy is absorbed and a part of it is reflected. As ω\omega approaches ωp\omega_p, all the free electrons are set to resonance together and all the energy is reflected. This is the explanation of high reflectivity of metals.Question: Taking the electronic charge as ee and the permittivity as ε0\varepsilon_0, use dimensional analysis to determine the correct expression for ωp\omega_p.

Options

  1. ANemε0\sqrt{\frac{N e}{m \varepsilon_0}}
  2. Bmε0Ne\sqrt{\frac{m \varepsilon_0}{N e}}
  3. CNe2mε0\sqrt{\frac{N e^2}{m \varepsilon_0}}
  4. Dmε0Ne2\sqrt{\frac{m \varepsilon_0}{N e^2}}

Correct answer

C. Ne2mε0\sqrt{\frac{N e^2}{m \varepsilon_0}}

Step-by-step solution

N=N= Number of electrons per unit volume ∴[N]=[L−3],[e]=[q]=[It]=[AT][ε0]=[M−1L−3T4A2]\begin{aligned} \therefore \quad[ N] & =\left[\mathrm{L}^{-3}\right],[ e]=[q] \\ & =[I t]=[\mathrm{AT}]\\ {\left[\varepsilon_0\right] } & =\left[\mathrm{M}^{-1} \mathrm{ L}^{-3} \mathrm{ T}^4 \mathrm{ A}^2\right] \end{aligned}Substitutingthethedimensions, we can see that, \left.\sqrt{\frac{N e^2}{m \varepsilon_0}}\right]=\left[\mathrm{T}^{-1}\right] Angular frequency has also the dimension \left[\mathrm{T}^{-1}\right].∴\therefore Correct option is (c). Analysis of Question (i) From calculation point of view, question is moderately difficult. Otherwise it is simple. (ii) Students may commit a mistake in the dimensions of $N. It is not dimensionless.
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