Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced2020PhysicsWork, Power and EnergyActual

A point charge q of mass m is suspended vertically by a string of length l . A point dipole of dipole moment p → is now brought towards q from infinity so that the charge moves away. The final equilibrium position of the system including the direction of the dipole, the angles and distances is shown in the figure below. If the work done in bringing the dipole to this position is N × ( m g h ) , where g is the acceler

Correct answer

0

Step-by-step solution

W = q V + m g h = q k p x 2 + m g h . . . 1 For equilibrium q E sin β = m g sin 90 - α 2 q E sin ( 180 - α ) = m g cos α 2 ; q E sin α = m g cos α 2 9 E 2 sin α 2 cos α 2 = m g cos α 2 ; q E = 2 mg sin α 2 q k p x 2 = m g x sin ( α 2 ) = m g sin α 2 · h sin α 2 q k p x 2 = m g h . . . 2 From (1) and (2) W = 2 m g h x = 2

Practice Work, Power and Energy on Quantrex Academy →

More from Work, Power and Energy

All Work, Power and Energy questions Full Work, Power and Energy list All JEE Advanced PYQs