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AP EAMCET202315 May 2023Evening ShiftChemistryChemical Bonding and Molecular StructureActual

Which of the following sets is correct?

Options

  1. AI
  2. BII
  3. CIII
  4. DIV

Correct answer

A. I

Step-by-step solution

SiH ₄ : Si belongs to group 14 , has 4 valence electrons, undergoes sp ^3 - hybridization to form a tetrahedral geometry. Be in BeCl ₂ is in sp-hybridization and forms linear shape. S in SF ₄ is in dsp ^3 - hybridization and forms a squarepyramidal geometry with one lone pair. SnCl ₂ has Sn in sp ^2 - hybridization and forms an angular geometry with one lone pair. Thus, only I is correct.

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