The bond order of dioxygen is ' m '. The bond order values of N ₂⁺ and C ₂²⁻ are respectively

Step-by-step solution

Given that, the bond order of dioxygen is m . Electronic configuration of O ₂(Z=16)= array r [ (1 s)]^2 [ ^*(1 s) ]^2[ (2 s)]^2 [ ( ^* 2 s ) ]^2 [ (2 p_z ) ]^2 [ (2 p_x ) ]^2 [ (2 p_y ) ]^2 [ ^* (2 p_x ) ] [ ^* (2 p_y ) ] array Bond order of oxygen = 1 2 (10-6)=2 Thus, value of m=2 Now, electronic configuration of N ₂⁺ is array r [ (1 s)]^2 [ ^*(1 s) ]^2[ (2 s)]^2 [ ( ^* 2 s ) ]^2 [ (2 p_x ) ]^2 [ (2 p_y ) ]^2 [ (2 p_z ] . array Bond order of N ₂⁺= 9-4 2 = 5 2 =2.5 and electronic configuration of C ₂²⁻ is aligned .