Arrange the following in the correct order of their bond orders.

Step-by-step solution

Bond order is the number of chemical bonds present between two atoms of a molecule. I. N ₂= 1 s^2, ^* 1 s^2, 2 s^2, ^* 2 s^2, 2 p_x^2= 2 p_y^2, 2 p_z^2 Bond order = 10-4 2 =3 II. O ₂= 1 s^2, ^* 1 s^2, 2 s^2, ^* 2 s^2, 2 p_z^2, 2 p_x^2 2 p_y^2, ^* 2 p_x^1 ^* 2 p_y^1 Bond order = 10-6 2 =2 III. O ₂⁺= 1 s^2, ^* 1 s^2, 2 s^2, ^* 2 s^2, 2 p_z^2, 2 p_x^2 2 p_y^2 , ^* 2 p_x^1 Bond order = 10-5 2 =2.5 IV. O ₂⁻= 1 s^2, ^* 1 s^2, 2 s^2, ^* 2 s^2, 2 p_z^2, 2 p_x^2 2 p_y^2 , ^* 2 p_x^2 ^* 2 p_y^1 Bond order = 10-7 2 =1.5 Hence