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AP EAMCET202120 Aug 2021Evening ShiftChemistryChemical Bonding and Molecular StructureActual

A covalent molecule X - Y is found to have a dipole moment of 1 . 5 × 10 - 29 C . m and a bond length of 150 pm . The percent ionic character of the bond will be

Options

  1. A50 %
  2. B62 . 5 %
  3. C75 %
  4. D80 %

Correct answer

B. 62 . 5 %

Step-by-step solution

Dipole moment= q × d Bond length d = 150 pm = 150 × 10 - 12 m Charge q = 1 . 6 × 10 - 19 Dipole moment = 150 × 10 - 12 × 1 . 6 × 10 - 19 = 2 . 4 × 10 - 29 Percentage ionic character = Dipole   observed Dipole   calculated × 100 Dipole observed = 1 . 5 × 10 - 29 Percentage ionic character = 1 . 5 × 10 - 29 2 . 4 × 10 - 29 × 100 = 62 . 5 Hence, the percent ionic character of the bond will be 62 . 5 % .

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