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AP EAMCET202119 Aug 2021Evening ShiftChemistryChemical Bonding and Molecular StructureActual

Match the following? Molecule Geometry (a) SnCl 2 (i) Angular (or) Bent (b) XeF 4 (ii) See-saw (c) ClF 3 (iii) Square pyramidal (d) IF 5 (iv) T-shape Square planar

Options

  1. A( a − i ) , ( b − ii ) , ( c − v ) , ( d − v )
  2. B( a − iv ) , ( b − v ) , ( c − i ) , ( d − ii )
  3. C( a − i ) , ( b − v ) , ( c − iv ) , ( d − iii )
  4. D( a − iv ) , ( b − iii ) , ( c − ii ) , ( d − v )

Correct answer

C. ( a − i ) , ( b − v ) , ( c − iv ) , ( d − iii )

Step-by-step solution

The hybridization of tin in SnCl 2 is sp 2 and it has one lone pair and two bond pairs. Hence, geometry should be Bent shape. The hybridisation of xenon in XeF 4 is sp 3 d 2 and it has two lone pairs and four bond pairs. Hence, geometry should be square planar. The hybridisation of chlorine in ClF 3 is sp 3 d and it has three lone pairs and three bond pairs. Hence, geometry should be T-shape. The hybridisation of Iodine in IF 5 is sp 3 d 2 and it has one lone pair and five bond pairs. Hence, geometry should be squa

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