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AP EAMCET202022 Sep 2020Morning ShiftChemistryChemical Bonding and Molecular StructureActual

Arrange O ₂, O ₂ [A s ~F ₆ ], KO ₂ in the increasing order of bond length of O - O bond.

Options

  1. AO ₂ < KO ₂ < O ₂ [ AsF ₆ ]
  2. BKO ₂ < O ₂ < O ₂ [ AsF ₆ ]
  3. CO ₂ [ AsF ₆ ] < KO ₂ < O ₂
  4. DO ₂ [ AsF ₆ ] < O ₂ < KO ₂

Correct answer

D. O ₂ [ AsF ₆ ] < O ₂ < KO ₂

Step-by-step solution

Bond length 1 Bond order In . K ₂ O ₂ ) or O ₂⁻ bond order is 1.5 . In O ₂ bond order is 2 . In O ₂ ( AsF ₆ ) or O ₂⁺ bond order is 2.5 . Hence, the correct order is O ₂ ( AsF ₆ ) < O ₂ < KO ₂ .

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