Observe the following molecules / ions ( H ₂, ~N ₂, O ₂, ~N ₂⁺, O ₂⁺, O ₂⁻, F ₂ ). Identify correct statement.

Step-by-step solution

( H ₂-( l s)^2 ) ( H ₂ ) does not have any unpaired electron hence diamagnetic in nature. ( N ₂ K K^ ( 2 ~s )^2 ( ^* 2 ~s )^2 ( 2 p_x )^2 ( 2 p_y )^2 ( p_z )^2 ) ( N ₂ ) does not have any unpaired electron hence diamagnetic in nature. ( array r O ₂ K K^1( 2 s)^2 ( ^* 2 s )^2 ( 2 p_z )^2 ( 2 p_x )^2 ( 2 p_y )^2 ( ^ 2 p_x )^1 ( ^ 2 p_y )^1 array ) ( O ₂ ) have two unpaired electrons hence paramagnetic in nature. ( N ₂⁺ K K^1( 2 s)^2 ( ^* 2 s )^2 ( 2 p_x )^2 ( 2 p_y )^2 ( 2 p_z )^1 ) ( N ₂ ) have one unpaired electron