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AP EAMCET201823 Apr 2018Morning ShiftChemistryChemical Bonding and Molecular StructureActual

X and Y are the two covalent molecules in which the hybridisation of the central atoms is same, but shapes are different. X and Y are

Options

  1. AXeF ₄, NH ₃
  2. BXeF ₂, PF ₅
  3. CBF ₃, H ₂ O
  4. DCH ₄, BeCl ₂

Correct answer

D. CH ₄, BeCl ₂

Step-by-step solution

The hybridisation in XeF ₂ and PF ₅ both is s p^3 d thus they must have trigonal bi-pyramidal geometry. But, due to the presence of 3 lone pair and 2 bond pair shape of XeF ₂ get distorted and the molecule appears linear. But in case of PCl ₅ this is not so.

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