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AP EAMCET201822 Apr 2018Morning ShiftChemistryChemical Bonding and Molecular StructureActual

XeF ₄ is square planar where as CCl ₄ is tetrahedral because

Options

  1. Ain XeF ₄ , ' Xe ' is s p^2 hybridised and in CCl ₄ ' C ' is s p^3 hybridised
  2. Bin both XeF ₄ and CCl ₄ the central atom is s p^3 hybridised
  3. Cin XeF ₄ , ' Xe ' is s p^3 d^2 hybridised but due to the presence of 2 lone pairs of electrons shape is square
  4. DX e is noble gas, whereas C is a non-metal

Correct answer

C. in XeF ₄ , ' Xe ' is s p^3 d^2 hybridised but due to the presence of 2 lone pairs of electrons shape is square

Step-by-step solution

XeF ₄ is s p^3 d^2 hybridised due to 4 +2 l p and shape is square planar. CCl ₄ is s p^3 hybridised due to 4 -bond.

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