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The number of real roots of the equation e^ x^1 + x+x-2=0, x 0 , is

Options

  1. A0
  2. B1
  3. C2
  4. D3

Correct answer

B. 1

Step-by-step solution

We have, e^ x-1 + x+x-2=0 Let f(x)=e^ x-1 + x+x-2 f^ (x)=e^ x-1 + 1 x +1 f^ (x)>0, x R f(x) is monotonic increasing function. Hence, f(x) has only one real roots.

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