If a=(x)/(y-z), b=(y)/(z-x) and c=(z)/(x-y) , where x, y and z are not all zero, then what is the value of a b+b c+c a= ?

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Correct answer: B. -1

We have, a= (x)/(y-z), b= (y)/(z-x), c= (z)/(x-y) where, x, y, z ≠ 0 Put x=1, y=2 and z=3 aligned & a=(1)/(2-3)=-1 & b=(2)/(3-1)=1 & c=(3)/(1-2)=-3 aligned Now, a b+b c+c a=-1-3+3=-1 a b+b c+c a=-1

If a=(x)/(y-z), b=(y)/(z-x) and c=(z)/(x-y) , where x, y and z are...

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