JEE Main
- Exam
- JEE Main
- Subject
- Mathematics
- Chapter
- Basics of Mathematics
JEE Main · Mathematics · Basics of Mathematics
\ x ∈ ℝ: (14 x)/(x+1)-(9 x-30)/(x-4) < 0\ is equal to
\left\{x \in \mathbb{R}: \frac{14 x}{x+1}-\frac{9 x-30}{x-4} < 0\right\}

Options
- A
- B
- C
- D
Correct answer
D.
Step-by-step solution
30)(x+1)}{(x+1)(x-4)} < 0\frac{14 x^2-56 x-\left(9 x^2-30 x+9 x-30\right)}{(x+1)(x-4)} < 0\frac{\left(14 x^2-56 x-9 x^2+30 x-9 x+30\right)}{(x+1)(x-4)} < 0\frac{\left(5 x^2-35 x+30\right)}{(x+1)(x-4)} < 0\frac{\left(x^2-7 x+6\right)}{(x+1)(x-4)} < 0, \frac{(x-1)(x-6)}{(x+1)(x-4)} < 0x \in(-1,1) \cup(4,6)