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JEE Main
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JEE Main
Subject
Mathematics
Chapter
Basics of Mathematics

JEE Main · Mathematics · Basics of Mathematics

\ x ∈ ℝ: (14 x)/(x+1)-(9 x-30)/(x-4) < 0\ is equal to

\left\{x \in \mathbb{R}: \frac{14 x}{x+1}-\frac{9 x-30}{x-4} < 0\right\}isequaltois equal to\ x ∈ ℝ: (14 x)/(x+1)-(9 x-30)/(x-4) < 0\ is equal to

Options

  1. A(−1,4)(-1,4)
  2. B(1,4)∪(5,7)(1,4) \cup(5,7)
  3. C(1,7)(1,7)
  4. D(−1,1)∪(4,6)(-1,1) \cup(4,6)

Correct answer

D. (−1,1)∪(4,6)(-1,1) \cup(4,6)

Step-by-step solution

30)(x+1)}{(x+1)(x-4)} < 0\frac{14 x^2-56 x-\left(9 x^2-30 x+9 x-30\right)}{(x+1)(x-4)} < 0\frac{\left(14 x^2-56 x-9 x^2+30 x-9 x+30\right)}{(x+1)(x-4)} < 0\frac{\left(5 x^2-35 x+30\right)}{(x+1)(x-4)} < 0\frac{\left(x^2-7 x+6\right)}{(x+1)(x-4)} < 0, \frac{(x-1)(x-6)}{(x+1)(x-4)} < 0Drawnnumberline,<br/><imgsrc="/api/proxy−image?url=httpsHence,Drawn number line,<br/><img src="/api/proxy-image?url=https%3A%2F%2Ffirebasestorage.googleapis.com%2Fv0%2Fb%2Fquantrexacademy-app.firebasestorage.app%2Fo%2Fquestions%252Ffigs%252Fquizrr%252Fquestion-assets%252F99_percentile_module%252FAWKhL2FQdLK32BIeHxNrG6nuJOX7BpNsGzGdrA_Y-UI.original.fullsize.png%3Falt%3Dmedia \text{ and } clean=1 \text{ and } v=qxfig138"/ data-qx-orig-src="/assets/diagrams/qx-book-c5319e8ea15ffcc3.png" data-qx-storage-src="/assets/diagrams/qx-book-c5319e8ea15ffcc3.png"><br/> Hence,x \in(-1,1) \cup(4,6)
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