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Exam
JEE Main
Subject
Mathematics
Chapter
Basics of Mathematics

JEE Main · Mathematics · Basics of Mathematics

If m, n are any two integers and~ m and n ~are related as m = n^ 2...

If m,nm, n are any two integers and~m and nm \text{ and } n~are related as m=n2−nm = n^{2} - n,~Then the expression~m2−2mm^{2} - 2m is always divisible by

Options

  1. A2424
  2. B99
  3. C1616
  4. D1818

Correct answer

A. 2424

Step-by-step solution

Given,& m=n2−nm = n^{2} - n

m=n(n−1).m = n \left(n - 1\right) .

m2−2m=m(m−2)m^{2} - 2m = m\left(m - 2\right)

=n(n−1)(n2−n−2)= n \left(n - 1\right) \left(n^{2} - n - 2\right)

= n \left(n - 1\right)\left(n + 1\right) \left(n - 2\right)

m^{2} - 2m = \left(n - 2\right) \left(n - 1\right)n \left(n + 1\right).<br/><br/>Itistheproductof.<br /><br />It is the product of4 consecutiveintegers.<br/><br/>~consecutive integers.<br /><br />∴ m^{2} - 2mmustbedivisiblebymust be divisible by24.</p>.</p>

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