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99 Percentile Qs Bank for JEE MainMathematicsBinomial Theorem

The nineth term in the expansion of 3 log 3 2 5 x - 1 + 7 + 3 - 1 / 8 log 3 5 x - 1 + 1 1 0 is equal to 180 , then x is -

Options

  1. A2
  2. B1
  3. C4
  4. DNone of these

Correct answer

B. 1

Step-by-step solution

We have, 3 log 3 2 5 x - 1 + 7 + 3 - 1 / 8  log 3 5 x - 1 + 1 1 0 = 2 5 x - 1 + 7 + 5 x - 1 + 1 - 1 / 8 1 0 ∵  a log a  N = N Here, T 9   =   180 , ⇒    1 0 C 8 2 5 x - 1 + 7 1 0 - 8 5 x + 1 + 1 - 1 / 8 8 = 1 8 0 ⇒    1 0 C 8 2 5 x - 1 + 7 5 x + 1 + 1 - 1 = 1 8 0 ⇒    4 5 2 5 x + 1 + 7 5 x - 1 + 1 = 1 8 0 ⇒    2 5 x - 1 + 7 5 x - 1 + 1 = 4 ⇒    y 2 + 7 y + 1 = 4 , where, y = 5 x -

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