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99 Percentile Qs Bank for JEE MainMathematicsProbability

A random variable X has the following probability distribution array |c|c|c|c|c|c|c|c|c| X = x & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 P ( X = x ) & 0.15 & 0.23 & k & 0.10 & 0.20 & 0.08 & 0.07 & 0.05 array For the events E= x / x is a prime number and F= x / x < 4 then P(E F)=

Options

  1. A0.57
  2. B0.87
  3. C0.77
  4. D0.35

Correct answer

C. 0.77

Step-by-step solution

P =10.15+0.23+ K +0.10+0.20+0.08+0.07+0.05=1 aligned & 0.88+ K =1 & ~K =0.12 & E = x: x is a prime number & E = 2,3,5,7 & F = 1,2,3 & E F = 1,2,3,5,7 & P ( E F )= P ( X =1)+ P ( X =2)+ P ( X =3)+ P ( X =5) & + P ( X =7) aligned =0.15+0.23+0.12+0.20+0.07=0.77

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