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An experiment yields 3 mutually exclusive and exhaustive events A , B and C . If P A = 2 P ( B ) = 3 P C , then P A is equal to

Options

  1. A1 11
  2. B2 11
  3. C3 11
  4. D6 11

Correct answer

D. 6 11

Step-by-step solution

Given, events A , B and C are mutually exclusive and exhaustive, hence P A ∪ B ∪ C = 1 ⇒ P A + P B + P C = 1 ⇒ P A + 1 2 P A + 1 3 P A = 1 ⇒ 11 6 P A = 1 ⇒ P A = 6 11

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