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If the bi-quadratic equation f ( x ) = x 4 + 2 x 3 - 16 x 2 - 22 x + 7 = 0 has 2 + 3 as one of its roots, then which of the following is not a root of f x ?

Options

  1. A3 - 2
  2. B2 - 3
  3. C- 3 + 2
  4. D- 3 - 2

Correct answer

A. 3 - 2

Step-by-step solution

Given, f ( x ) = x 4 + 2 x 3 - 16 x 2 - 22 x + 7 = 0 ∵   2 + 3 is one of the roots of f x = 0 ∴   2 - 3 is also one of the roots of f x = 0 Let us assume the other two roots of the f x = 0 are α ,   β ⇒ Sum of roots = - 2 ⇒ α + β + 2 + 3 + 2 - 3 = - 2 ⇒ α + β = - 6   … i And product of roots = 7 ⇒ α β 2 + 3 2 - 3 = 7 ⇒ α β = 7   … ii Put β = 7 α in equation i , we get ⇒ &#

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