99 Percentile Qs Bank for JEE MainPhysicsAlternating Current
A capacitor 50 F is connected to a power source V=220 50 t ( V in volt, t in second). The value of rms current (in ampere)
Options
- A2 0.55 ~A
- B0.55 ~A
- C2 ~A
- D(0.55) 2 ~A
Correct answer
D. (0.55) 2 ~A
Step-by-step solution
The given aligned & C=50 F =50 10⁻⁶ ~F & V=220 50 t aligned But we know that V=V₀ t Comparing both equations V₀=220 ~V , =50 rad / s The capacitive reactance of the circuit is aligned X_C & = 1 C & = 1 50 50 10⁻⁶ =400 aligned The peak and the rms values of current in the circuit are i₀= V₀ X_C = 220 400 = 11 20 and aligned i_ ms & = i₀ 2 & = 11 / 20 2 = 0.55 2 ~A aligned