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99 Percentile Qs Bank for JEE MainPhysicsAlternating Current

When an inductor (L ) and a resistor (R ) in series are connected across a (12 ~V , 50 ~Hz ) supply, a current of 0.5 A flows in the circuit. The current differs in the phase from applied voltage by ( 3 ) radian. Then the value of (R ) is

Options

  1. A(10 )
  2. B(3 )
  3. C(12 )
  4. D(15 )

Correct answer

C. (12 )

Step-by-step solution

Given situation following the figure below, Given for AC circuit, (V_ rms =12 ~V , ) frequency, (f=50 ~Hz ), current, ( I=0.5 ~A ), phase difference, ( = 3 ) ( ) Impedance of the AC circuit, (Z= V_ rms I = 12 0.5 Z=24 ) Power factor, ( = R Z 3 = R 24 1 2 = R 24 R=12 )

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