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99 Percentile Qs Bank for JEE MainPhysicsAlternating Current

The coils of a step-down transformer have 500 and 5000 turns. In the primary coil an ( AC ) current of (4 ~A ) at (2200 ~V ) is sent. The value of the current and potential difference in the secondary coil is

Options

  1. A(20 ~A , 220 ~V )
  2. B(0.4 ~A , 22000 ~V )
  3. C(40 ~A , 220 ~V )
  4. D(40 ~A , 22000 ~V )

Correct answer

C. (40 ~A , 220 ~V )

Step-by-step solution

For a step-down transformer, ( aligned N_P & =5000, N_S=500 I_P & =4 ~A , V_P=2200 ~V aligned ) For a transformer, we know that ( aligned & N_S N_P = V_S V_P = I_P I_S & Using, N_S N_P = V_S V_P & V_S= N_S V_P N_P = 500 2200 5000 =220 ~V & Again, using V_S V_P = I_P I_S & I_S= I_P V_P V_S = 4 2200 220 =40 ~A aligned )

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