The instantaneous current and voltage of an AC circuit are given by i = 10 sin 314 t A and V = 100 sin 314 t V . What is the power dissipation in the circuit?

Step-by-step solution

Given, I = 10 sin 314 t A and V = 100 sin 314 t V Comparing with I = I 0 sinωt and V = V 0 sinωt , we get ∴ I 0 = 10 A and V 0 = 100 V ⇒ I rms = 10 2 A, V rms = 100 2 V, Phase difference ϕ =0 o ∴ Power dissipated P av = V rms × I rms × cosϕ = ( 10 2 ) ( 100 2 ) cos 0 o = 500 W