99 Percentile Qs Bank for JEE MainPhysicsAlternating Current
In series R - L - C circuit, the root mean square voltage across the resistor and inductor are respectively 400 V and 700 V . If the equation for the applied voltage is E = 500 2 sin ω t V , then the peak voltage across the capacitor is
Options
- A1200 V
- B1200 2 V
- C400 V
- D400 2 V
Correct answer
D. 400 2 V
Step-by-step solution
V R 2 + V L - V C 2 = E r m s 2 V L - V C 2 = 500 2 - 400 2 V L - V C = ( 500 ) 2 - ( 400 ) 2 = 300 V C = V L - 300 = 700 - 300 = 400 V ∴ V C p e a k = V C 2 = 400 2 V