99 Percentile Qs Bank for JEE MainPhysicsAtomic Physics
Assuming the atom in the ground state, the expression for the magnetic field at a point (nucleus) in hydrogen atom due to circular motion of electron is [ ₀= . permeability of free space, ₀= permittivity of free space, m = mass of electron, e = electronic charge, h = Planck's constant ]
Options
- A₀ e⁷ m² 8 ₀³ h⁵
- B₀ m² e⁵ 8 ₀³ h³
- C₀ m e⁴ 8 ₀³ h³
- D₀ m³ e⁴ 8 ₀² h²
Correct answer
A. ₀ e⁷ m² 8 ₀³ h⁵
Step-by-step solution
Magnetic field at the centre of a circular coil is given by B = _ o I 2 r ....(1) In the case of electron revolving around the nucleus, the current I can be written as I =ef where f is the frequency of revolution. f = V 2 r I = eV 2 r But for electron in ground state V= e² 2 ₀ h I = e ³ 4 _ o hr Putting this value in Eq (1) : B = _ o e ³ 8 _ o hr ² ...(2) But r= h² ₀ m e² Putting this value of r in Eq. (2) we get : B= ₀ e⁷ m² 8 ₀³ h⁵