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The ratio of the wavelengths for 2 → 1 transition in L i 2 + , He + and H is

Options

  1. A1 : 2 : 3
  2. B1 9 : 1 4 : 1 1
  3. C1 : 4 : 1
  4. D3 : 2 : 1

Correct answer

B. 1 9 : 1 4 : 1 1

Step-by-step solution

From Bohr’s formula , the wave number 1 λ is given by 1 λ = Z 2 R 1 n 1 2 - 1 n 2 2 where Z is atomic number, R the Rydberg's constant and n is the quantum number. ⇒ λ ∝ 1 Z 2 Atomic number of lithium is 3, of helium is 2 and of hydrogen is 1. ∴ λ Li 2 + : λ He + : λ H = 1 3 2 : 1 2 2 : 1 = 1 9 : 1 4 : 1

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