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A hydrogen atom in ground state absorbs 10.2 e V of energy. The orbital angular momentum of the electron is increased by

Options

  1. A1.05 × 1 0 – 34 J ⁡ s
  2. B2.11 × 1 0 – 34 J ⁡ s
  3. C3.16 × 1 0 – 34 J ⁡ s
  4. D4.22 × 1 0 – 34 J ⁡ s

Correct answer

A. 1.05 × 1 0 – 34 J ⁡ s

Step-by-step solution

Δ E = E 2 - E 1 10.2 e V = - 3.4 e V + 13.6 e V This is possible only when E 2 - 3.4 e V and E 1 = - 13.6 e V This mean n 2 = 2 & n 1 = 1 Δ L = 2 h 2 π - h 2 π = h 2 π = 6.63 × 10 - 34 2 × 3 . 14 J s = 1.05 × 1 0 – 34 J ⁡ s

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