99 Percentile Qs Bank for JEE MainPhysicsDual Nature of Matter
A charged particle is accelerated from rest through a certain potential difference. The de-Broglie wavelength is ₁ when it is accelerated through V₁ and is ₂ when accelerated through V₂ . The ratio ₁ / ₂ is
Options
- AV₁^ 3 / 2 : V₂^ 3 / 2
- BV₂^ 1 / 2 : V₁^ 1 / 2
- CV₁^ 1 / 2 : V₂^ 1 / 2
- DV₁^2: V₂^2
Correct answer
B. V₂^ 1 / 2 : V₁^ 1 / 2
Step-by-step solution
The de-Broglie wavelength associated with a charged particle is given by = h m q V where, h= planck's constant m= mass of charged particle q= charge on the particle V= potential at which the charged particle is accelerated. ₁= h m₁ q V₁ , ₂= h m₂ q V₂ Here, aligned m₁ & =m₂ ₁ ₂ & = m₂ q V₂ m₁ q V₁ = V₂ V₁ & =V₂^ 1 2 V₁^ 1 2 aligned