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A photon released by the transition of an electron from the second excited state to the ground state of Hydrogen atom is incident on the surface of a metal of work function 3.1 eV . The de Broglie wavelength of the most energetic electron emitted from that metal surface is nearly

Options

  1. A2.6 Å
  2. B4 Å
  3. C6 Å
  4. DNone of these

Correct answer

D. None of these

Step-by-step solution

Work function, W =3.1 eV aligned & hu =13.6 [ 1 n ₁^2 - 1 n ₂^2 ] & =13.6 [ 1 1^2 - 1 3^2 ]=13.6 [1- 1 9 ]=13.6 8 9 & =12.1 eV . aligned From Einstein's photoelectric equation aligned & hv = K _ + W & hc = hv - w & =12.1-3.1 & hc =9 eV & = 66 10⁻³⁴ 3 10^8 9 1.6 10⁻¹⁹ =1.3 10⁻⁷ ~m aligned

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