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When radiation of wavelength ' ' is incident on a metallic surface, the stopping potential is 4.8 ~V . If the surface is illuminated with radiation of double the wavelength then the stopping potential becomes 1.6 ~V .' The threshold wavelength for the surface is

Options

  1. A2
  2. B4
  3. C6
  4. D8

Correct answer

B. 4

Step-by-step solution

Stopping potential: aligned & eV ₀= h v- ₀ & eV ₀= hc - ₀ aligned For first case: e (4.8)= hc - ₀... (i) For Second case: e(1.6)= h c 2 - ₀... (ii) Dividing equation (i) by equation (ii), aligned & 3 ( hc 2 - ₀ )= hc - ₀ & 3 hc 2 -3 ₀= hc - ₀ & hc 2 =2 ₀ & hc 4 = ₀ aligned Threshold wavelength is 4 .

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