99 Percentile Qs Bank for JEE MainPhysicsDual Nature of Matter
Following graph shown the variation of stopping potential corresponding to the frequency of incident radiation (v) for a given metal. The correct variation is shown in graph [ v₀= threshold frequency]
Options
- A(C)
- B(B)
- C(A)
- D(D)
Correct answer
C. (A)
Step-by-step solution
Concept: Stopping potential V is related to the maximum kinetic energy K_ of the photoelectrons, via Einstien's photo-electric effect relation: e V=K_ =h v-h v₀ Therefore, V= ( h e ) v- ( h e ) v₀ Therefore, V vs v is straighline with positive slope and at v=v₀ the stopping potential is zero.