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In the following arrangement, y = 1 . 0   mm , d = 0 . 24   mm and D = 1 . 2   m . The work function of the material of the emitter is 2 . 2   eV . The stopping potential V ' needed to stop the photocurrent will be:

Options

  1. A0 . 9   V  
  2. B0 . 5   V
  3. C0 . 4   V
  4. D0 . 1   V

Correct answer

A. 0 . 9   V  

Step-by-step solution

In Young's double slit experiment, Fringe Width, β = λ D d Distance between dark and bright fringe = y . So, β = 2 y λ D d = 2 y λ = 2 × 1 × 10 - 3 × 0 . 24 × 10 - 3 1 . 2   A o λ = 4000   A o Energy of photon light incident, E = 12400 λ A o E ( in   eV ) = 12400 4000 E = 3 . 1   eV To calculate the stopping potential V ' applying Einstein's photoelectric equation, E ( eV ) = W 0 + e V ' ⇒ 3 . 1   eV = 2 . 2  

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